Take Note: Give me a step-by-step solution 1. A butane isomerization process produces 70 kmol/hr of pure isobutane. A purge stream is removed continuously and contains 85% n-butane and 15% impurity (mole%). The feed stream is butane containing % impurity (mole%). The flow rate of the purge stream will be A. 3 kmol/hr B. 4 kmol/hr C. 5 kmol/hr D. 6 kmol/hr.
Take Note: Give me a step-by-step solution 1. A butane isomerization process produces 70 kmol/hr of pure isobutane. A purge stream is removed continuously and contains 85% n
VIDEO ANSWER: Even Massu inserts at the option as the biceps break. There is a city called tubarao. I'm talking about action. There is a reflection of elbow an…
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SOLVED:n-Butane is converted to isobutane in a continuous isomerization reactor that operates isothermally at 149^∘ C . The feed to the reactor contains 93 mole % n -butane, 5 % isobutane, and 2 % HCl at 149^∘ C, and a 40 % conversion of n -butane is achieved. (a) Taking a basis of 1 mol of feed gas, calculate the moles of each component of the feed and product mixtures and the extent of reaction, ξ(b) Calculate the standard heat of the isomerization reaction (kJ). Then, taking the feed and prod
SOLVED:n-Butane is converted to isobutane in a continuous isomerization reactor that operates isothermally at 149^∘ C . The feed to the reactor contains 93 mole % n -butane, 5 % isobutane, and 2 % HCl at 149^∘ C, and a 40 % conversion of n -butane is achieved. (a) Taking a basis of 1 mol of feed gas, calculate the moles of each component of the feed and product mixtures and the extent of reaction, ξ(b) Calculate the standard heat of the isomerization reaction (kJ). Then, taking the feed and prod
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